sag amount vs. No. of turns on ring nut?

I had no luck with my search on this topic even though I remember reading it maybe a year ago or so...

Does anybody have a rule of thumb on how many turns it takes on the spring pre-load ring nut that will give you about 5mm of race sag?

I don't know if it is the same for the WR250F, which is what I have. But one turn = 1.5mm so you would be about 3 1/3 turns.

better get confirmation from a big bore though.




2001 WR250F

1975 KZ900 - project bike

I don't think 3.5 turns is right. That's the shock travel difference, not the sag difference (5.5" of shock travel=over 12" of suspension travel)

I've found that slight movements in the rings make a BIG difference here. Mark where you are with a crayon so we can guage how far you turned the rings. Try just 3 "knotches" first and measure...IMHO

I would think that the number of turns of the ring nut and resulting sag would be dependent on the weight of rider and gear. What do I know though?...I work in a grocery store.

My .02

Good Luck,



Bryce Senff

WMRRA #201




Oh it's Good to Be Back on a Dirtbike!

Gotta go with Bryce on this one...race sag will be determined by rider weight w/ gear...

free sag will be determined by how worked over the rear spring is(even fresh springs will have a slight variations if you throw them on a spring tester) way to determine these settings by # of turns unless you were consistent on the rest of the variables in the equation. Turn and measure is still the accurate way to set sag.

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now