- 20 cm
^{2} - 24 cm
^{2} - 30 cm
^{2} - NOT

Option 2 : 24 cm^{2}

**GIVEN:**

Diagonal (Let BD) = 8cm

Side = 5cm

**FORMULA USED:**

Area of Rhombus = 1/2 × d_{1} × d_{2}

**CALCULATION:**

** **

Using Pythagoras Theroem,

In Triangle ABE

⇒ AE2 = AB2 - BE2

⇒ AE = 25 - 16 = 9

∴ AE = 3 cm and AC = 2 × 3 = 6 cm

Area of Rhombus = 1/2 × d1 × d2

⇒ 1/2 × 8 × 6 = 24

∴ **Area of the Rhombus = 24 cm ^{2}**

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 2,19,51,419+ Students

Testbook Edu Solutions Pvt. Ltd.

1st & 2nd Floor, Zion Building,

Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

support@testbook.com
Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

Toll Free:1800 833 0800

Office Hours: 10 AM to 7 PM (all 7 days)